android用脚本提取固定字符串转为使用string.xml

• 2013-11-08
• android 9
• python 7
• i18 1

• 本例是要把appendMonitorLog("xxxxx")格式的字符串提取出来写入string.xml 不同需求更改正则表达式
• 脚本所做工作:
  1. 将java文件中匹配的字符串转为使用string id
  2. 在string.xml加入对应项

     #!/usr/bin/python
     # coding=utf8
     
     import os,sys,re
     
     srcdir='src/main/java/com/sangame/xx/android/'
     xml='res/values/strings.xml'
     xmlsf='\n    <string name="{0}">{1}</string>\n'
     stridf='message{0}'
     rbf='MonitorService.getService().getResources().getString(R.string.{0})'
     sp=r'(?P<pre>appendMonitorLog\()"(.+?)"(?P<end>\))' #按需修改
     
     def add2xml(strid,msg):
         xmls = xmlsf.format(strid,msg)
         with open(xml) as f:
             s = f.read()
         p=r'(\n)(?P<end>\n</resources>)'
         s = re.sub(p,xmls+'\g<end>',s)
         with open(xml,'w') as f:
             f.write(s)
     
     startid=100
     i=startid
     msgs=[]
     def getstrid(msg):
         if msg in msgs:
             return stridf.format(msgs.index(msg)+startid)
         else:
             global i
             msgs.append(msg)
             strid=stridf.format(i)
             i = i + 1
             add2xml(strid,msg)
             return strid
     
     
     for root,dirs,files in os.walk(srcdir):
         for file in files:
             p = os.path.join(root,file)
             print(p)
             with open(p) as f:
                 s=f.read()
     
             m=re.findall(sp,s)
             count = len(m)
             print(m)
     
             if m:
                 for j in range(len(m)):
                     strid=getstrid(m[j][1])
                     rb=rbf.format(strid)
                     if j == 0:
                         ns,n=re.subn(sp,'\g<pre>'+rb+'\g<end>',s,count=1)
                     else:
                         ns,n=re.subn(sp,'\g<pre>'+rb+'\g<end>',ns,count=1)
                 with open(p,'w') as f:
                     f.write(ns)
     

若是少量漏网的可以另外处理,比如

        m=re.findall(sp,s)
        for s in m:
            if '+' in s:
                print(p)
                print(s)
        continue